Ln(2+2x+x^2)=[ln(0.862)]+x

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Solution for Ln(2+2x+x^2)=[ln(0.862)]+x equation: 


Simplifying
Ln(2 + 2x + x2) = [ln(0.862)] + x
(2 * nL + 2x * nL + x2 * nL) = [ln(0.862)] + x
(2nL + 2nxL + nx2L) = [ln(0.862)] + x

Reorder the terms for easier multiplication:
2nL + 2nxL + nx2L = [0.862ln] + x

Solving
2nL + 2nxL + nx2L = [0.862ln] + x

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '[-0.862ln]' to each side of the equation.
2nL + 2nxL + [-0.862ln] + nx2L = [0.862ln] + [-0.862ln] + x

Reorder the terms:
[-0.862ln] + 2nL + 2nxL + nx2L = [0.862ln] + [-0.862ln] + x

Combine like terms: [0.862ln] + [-0.862ln] = 0.000
[-0.862ln] + 2nL + 2nxL + nx2L = 0.000 + x
[-0.862ln] + 2nL + 2nxL + nx2L = x

Combine like terms: x + -1x = 0
[-0.862ln] + 2nL + 2nxL + nx2L + -1x = 0

The solution to this equation could not be determined.

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